q^2+16q-225=0

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Solution for q^2+16q-225=0 equation:


Simplifying
q2 + 16q + -225 = 0

Reorder the terms:
-225 + 16q + q2 = 0

Solving
-225 + 16q + q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(-25 + -1q)(9 + -1q) = 0

Subproblem 1

Set the factor '(-25 + -1q)' equal to zero and attempt to solve: Simplifying -25 + -1q = 0 Solving -25 + -1q = 0 Move all terms containing q to the left, all other terms to the right. Add '25' to each side of the equation. -25 + 25 + -1q = 0 + 25 Combine like terms: -25 + 25 = 0 0 + -1q = 0 + 25 -1q = 0 + 25 Combine like terms: 0 + 25 = 25 -1q = 25 Divide each side by '-1'. q = -25 Simplifying q = -25

Subproblem 2

Set the factor '(9 + -1q)' equal to zero and attempt to solve: Simplifying 9 + -1q = 0 Solving 9 + -1q = 0 Move all terms containing q to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -1q = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -1q = 0 + -9 -1q = 0 + -9 Combine like terms: 0 + -9 = -9 -1q = -9 Divide each side by '-1'. q = 9 Simplifying q = 9

Solution

q = {-25, 9}

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